Teacher t;//学生1和学生2的引用值都是一样的。
Student(String name,int age,Teacher t){
this.name=name;
this.age=age;
this.t=t;
}
public Object clone(){
Student stu=null;
try{
stu=(Student)super.clone();
}catch(CloneNotSupportedException e){
e.printStackTrace();
}
stu.t=(Teacher)t.clone();
return stu;
}
public static void main(String[] args){
Teacher t=new Teacher("tangliang",30);
Student s1=new Student("zhangsan",18,t);
Student s2=(Student)s1.clone();
s2.t.name="tony";
s2.t.age=40;
System.out.println("name="+s1.t.name+","+"age="+s1.t.age);
//学生1的老师成为tony,age为40。
}
}
那应该如何实现深层次的克隆，即修改s2的老师不会影响s1的老师？代码改进如下。
class Teacher implements Cloneable{
String name;
int age;
Teacher(String name,int age){
this.name=name;
this.age=age;
}
public Object clone(){
Object obj=null;
try{
obj=super.clone();
}catch(CloneNotSupportedException e){
e.printStackTrace();
}
return obj;
}
}
class Student implements Cloneable{
String name;
int age;
Teacher t;
